Question

3b(b-2c)² + b(b²+c) если b=3, c=4​

Answer 1

Ответ:

$3b*(b^{2}-4bc+4c^{2} )+b^{3} +bc=3b^{3} -12b^{2}c+12c^{2}b+ b^{3} +bc=4b^{3}-12b^{2}c+12c^{2}b +bc=4*3^{3}-12*3^{2}*4+12*4^{2}*3+4*3= 108-432+576+12=264$

Объяснение:

Answer 2

To evaluate the expression 3b(b-2c)² + b(b²+c) when b=3 and c=4, we substitute the given values into the expression and perform the calculations.

Let's substitute b=3 and c=4 into the expression:

3b(b-2c)² + b(b²+c) = 3(3-2(4))² + 3(3²+4)

Now, let's simplify each part step by step:

3(3-2(4))² can be simplified as follows: = 3(3-8)² = 3(-5)² = 3(25) = 75

3(3²+4) can be simplified as follows: = 3(9+4) = 3(13) = 39

Now, let's substitute these simplified values back into the original expression:

75 + 39 = 114

Therefore, when b=3 and c=4, the expression 3b(b-2c)² + b(b²+c) evaluates to 114.