Question

Cos(-570°)+корен3sin(-300°)+2tg(-1350)​

Answer 1

Приложение photomath, бесплатное, много решает

Answer 2

To calculate the expression cos(-570°) + √3sin(-300°) + 2tg(-1350), we can use the trigonometric identities and convert the angles to their equivalent values within the range of 0° to 360°.

Let's simplify each term step by step:

1. cos(-570°): Since the cosine function has a period of 360°, we can subtract multiples of 360° to bring the angle within the range of 0° to 360°: -570° + 360° = -210°

Now, we can evaluate cos(-210°): cos(-210°) = cos(210°) ≈ 0.9397

2. √3sin(-300°): Again, let's bring the angle within the range of 0° to 360°: -300° + 360° = 60°

Now, we can evaluate sin(60°): sin(60°) = √3/2 ≈ 0.8660

Now, multiply by √3: √3sin(60°) = √3 * 0.8660 ≈ 1.732

3. 2tg(-1350): Let's bring the angle within the range of 0° to 360°: -1350° + 360° = -990°

Now, we can evaluate tg(-990°): tg(-990°) = tg(270°) = undefined

Since the tangent function is undefined at 90° and 270°, this term is undefined.

Putting it all together:

cos(-570°) + √3sin(-300°) + 2tg(-1350) = 0.9397 + 1.732 + undefined

Therefore, the value of the expression is undefined.