Question

(x^2+2x-24)/(x^2-4x) при x=0.003

Answer 1

$\dfrac{x^2+2x-24}{x^2-4x}= \dfrac{x^2-4x+6x-24}{x(x-4)}= \dfrac{x(x-4)+6(x-4)}{x(x-4)}= \dfrac{x+6}{x}$

подставляем x
$\dfrac{0,003+6}{0,003}= \dfrac{0,003}{0,003}+ \dfrac{6}{0,003}=1+ \dfrac{6000}{3}=1+2000=2001$

Answer 2

To evaluate the expression (x^2+2x-24)/(x^2-4x) at x = 0.003, we substitute the value of x into the expression and perform the calculations.

First, let's substitute x = 0.003 into the expression:

((0.003)^2 + 2(0.003) - 24) / ((0.003)^2 - 4(0.003))

Now, we simplify the expression:

((0.000009 + 0.006) - 24) / (0.000009 - 0.012)

(0.000015 - 24) / (-0.000003)

-23.999985 / -0.000003

Finally, performing the division:

= 7,999,995

Therefore, when x = 0.003, the expression (x^2+2x-24)/(x^2-4x) evaluates to 7,999,995.