Question

A)(4y^2+9)(2y-3)(2y+3) б)(7m^2-3n^3)(7m^2+3n^3)

Answer 1

Морі но у мене якась дія вийшла може це і є так

Answer 2

(4y^2+9)(2y-3)(2y+3)=(4y^2+9)(4y^2-9)=(16у^4-81)
(7m^2-3n^3)(7m^2+3n^3)=(49m^4-9n^6)

Answer 3

Let's simplify each expression:

a) (4y^2 + 9)(2y - 3)(2y + 3)

First, we can simplify the expression (2y - 3)(2y + 3) using the difference of squares formula: a^2 - b^2 = (a + b)(a - b).

(2y - 3)(2y + 3) = (2y)^2 - (3)^2 = 4y^2 - 9

Now we can substitute this simplified expression back into the original expression:

(4y^2 + 9)(4y^2 - 9)

Now we can apply the difference of squares formula again:

(4y^2)^2 - (9)^2 = 16y^4 - 81

Therefore, the simplified expression is 16y^4 - 81.

b) (7m^2 - 3n^3)(7m^2 + 3n^3)

This expression is already in the form of a difference of squares, so we can directly apply the formula:

(7m^2)^2 - (3n^3)^2 = 49m^4 - 9n^6

Therefore, the simplified expression is 49m^4 - 9n^6.