Question

(2х-1)(2х+1)-4(х+5)(квадрат)=19

Answer 1

(2х-1)(2х+1)-4(х+5)^2=19

4x^2-1- 4(x^2+10x+25)=19

4x^2-1- (4x^2+40x+100)=19

4x^2-1-4x^2-40x-100=19

-40х-101=19

-40х=101+19

-40x=120

x=-3

Ответ: -3

 

Answer 2

To solve the equation, let's simplify and expand the expressions:

(2x - 1)(2x + 1) - 4(x + 5)² = 19

Expanding the expressions:

(4x² - 1) - 4(x² + 10x + 25) = 19

Distributing the negative sign inside the parentheses:

4x² - 1 - 4x² - 40x - 100 = 19

Combine like terms:

4x² - 4x² - 40x - 1 - 100 = 19

-40x - 101 = 19

Now, isolate the term with x:

-40x = 19 + 101

-40x = 120

Divide both sides by -40:

x = 120 / -40

Simplifying:

x = -3

Therefore, the solution to the equation is x = -3.