Question

25х²=1;2х²-4=0;2х²+6=0

Answer 1

25х²=1
х²=1\25
х=1\5
х=-1\5

2х²-4=0
2х²=4
х²=2
х=√2
х=-√2

2х²+6=0
2х²=-6
х²=-3 выражение не имеет смысла

Answer 2

To solve the equations, let's tackle them one by one:

1. 25x² = 1

To solve this equation, we need to isolate x². We can divide both sides of the equation by 25:

(25x²)/25 = 1/25

Simplifying:

x² = 1/25

To remove the square root, we can take the square root of both sides:

√(x²) = ±√(1/25)

This gives us two possibilities:

x = ±1/5

So the solutions to the equation 25x² = 1 are x = 1/5 and x = -1/5.

2. 2x² - 4 = 0

To solve this equation, let's isolate x². Add 4 to both sides:

2x² - 4 + 4 = 0 + 4

Simplifying:

2x² = 4

Next, divide both sides by 2:

(2x²)/2 = 4/2

Simplifying:

x² = 2

Taking the square root of both sides:

√(x²) = ±√2

This gives us two possibilities:

x = ±√2

So the solutions to the equation 2x² - 4 = 0 are x = √2 and x = -√2.

3. 2x² + 6 = 0

To solve this equation, let's isolate x². Subtract 6 from both sides:

2x² + 6 - 6 = 0 - 6

Simplifying:

2x² = -6

Next, divide both sides by 2:

(2x²)/2 = -6/2

Simplifying:

x² = -3

Taking the square root of both sides, we encounter an issue. The square root of a negative number is not a real number. Therefore, this equation has no real solutions.

So the equation 2x² + 6 = 0 has no real solutions.