Question

Тело весом 20Н погрузили в воду. Вес вытесненной воды 12Н. Утонет ли это тело? (Плотность воды 1000кг/м^3). А)утонет Б)Будет плавать внутри жидкости) В)всплывёт.

Answer 1

Analysis and Solution

To determine whether the body will sink, float, or remain suspended in water, we need to compare the weight of the body with the weight of the water it displaces. If the weight of the body is greater than the weight of the water it displaces, the body will sink. If the weight of the body is less than the weight of the water it displaces, the body will float. If the weight of the body is equal to the weight of the water it displaces, the body will remain suspended in the water.

Given: - Weight of the body = 20 N - Weight of the displaced water = 12 N - Density of water = 1000 kg/m^3

To solve this problem, we can use the principle of Archimedes' buoyancy:

Archimedes' Principle: The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Calculation

To find the volume of water displaced by the body, we can use the formula:

Volume of water displaced = Weight of displaced water / Density of water

Substituting the given values:

Volume of water displaced = 12 N / 1000 kg/m^3

Calculating the volume:

Volume of water displaced = 0.012 m^3

Now, let's compare the weight of the body with the weight of the displaced water:

- Weight of the body = 20 N - Weight of the displaced water = 12 N

Since the weight of the body (20 N) is greater than the weight of the displaced water (12 N), the body will sink in the water.

Therefore, the correct answer is A) The body will sink.

Conclusion

Based on the given information, a body with a weight of 20 N and displacing 12 N of water will sink in water.