Question

50 БАЛЛОВ . Кинематический закон движения тела вдоль оси Ох имеет вид: x=A+Bt+Ct2, где А = 4 м, B = 3 м/с, С = -1,5 м/с2 чему равна Проекция скорости v0x на эту ось в начальный момент времени

Answer 1

Kinematic Law of Motion along the x-axis

The kinematic law of motion for a body along the x-axis is given by the equation: x = A + Bt + Ct^2, where A = 4 m, B = 3 m/s, and C = -1.5 m/s^2.

To find the projection of velocity v0x on this axis at the initial moment in time, we need to differentiate the equation for position x with respect to time t to obtain the equation for velocity v:

v = dx/dt = d(A + Bt + Ct^2)/dt = B + 2Ct.

Therefore, the projection of velocity v0x on the x-axis at the initial moment in time is equal to the coefficient B, which is 3 m/s.

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