Question

Прикладывая силу 100Н, груз массой 20кг равномерно подняли по наклонной плоскости. Длина наклонной плоскости равна 5м, высота - 2м. чему равен КПД наклонной плоскости?

Answer 1

Η = $\frac{A poleznaja}{A zatrachennaja}$ * 100 % = $\frac{m * g * h}{F * l}$

m - масса ( 20 кг )
g - ускорение свободного падения ( 10 Н/кг )
h - высота ( 2 м )
F - сила ( 100 Н )
l - длина ( 5 м )

η = $\frac{20 * 10 * 2}{100 * 5} = \frac{400}{500}$ = 0,8 * 100 = 80 % 

Answer 2

Calculation of Efficiency (КПД) of the Inclined Plane

To calculate the efficiency (КПД) of the inclined plane, we need to determine the work input and work output.

The work input is the product of the force applied and the distance over which it is applied. In this case, the force applied is 100 N and the distance is the length of the inclined plane, which is 5 m. Therefore, the work input is:

Work input = Force × Distance = 100 N × 5 m = 500 J

The work output is the product of the weight of the load and the height it is lifted. The weight of the load can be calculated using the mass and acceleration due to gravity. The mass of the load is 20 kg and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the load is:

Weight = Mass × Acceleration due to gravity = 20 kg × 9.8 m/s^2 = 196 N

The height the load is lifted is given as 2 m. Therefore, the work output is:

Work output = Weight × Height = 196 N × 2 m = 392 J

Now, we can calculate the efficiency (КПД) of the inclined plane using the formula:

Efficiency (КПД) = (Work output / Work input) × 100%

Substituting the values we calculated earlier:

Efficiency (КПД) = (392 J / 500 J) × 100% = 78.4%

Therefore, the efficiency (КПД) of the inclined plane is approximately 78.4%.