Question

Индуктивность катушки составляет 100 мГн. определите энергию магнитного поля если сила тока в цепи равна 25 А.

Answer 1

Энергия магнитного поля катушки с током равна половине произведения индуктивности катушки на квадрат силы тока. W = L*I² / 2. 
L = 100 мГн = 0,1 Гн.       W = 0,1 Гн*(25 А)² / 2 = 31,25 Дж

Answer 2

Calculation of Magnetic Field Energy

To calculate the energy of a magnetic field in a coil, we need to use the formula:

Energy (W) = (1/2) * L * I^2

Where: - L is the inductance of the coil in henries (H) - I is the current flowing through the coil in amperes (A)

Given that the inductance of the coil is 100 mH (millihenries) and the current in the circuit is 25 A, we can substitute these values into the formula to find the energy of the magnetic field.

Energy (W) = (1/2) * 0.1 H * (25 A)^2

Calculating this expression gives us the energy of the magnetic field in watts.

Let's calculate it:

Energy (W) = (1/2) * 0.1 H * (25 A)^2 = 0.5 * 0.1 H * 625 A^2 = 31.25 Joules

Therefore, the energy of the magnetic field in the coil is 31.25 Joules.

Please note that the calculation assumes ideal conditions and neglects factors such as resistance and losses in the coil.

Conclusion

The energy of the magnetic field in the coil with an inductance of 100 mH and a current of 25 A is 31.25 Joules.

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