Question

Автомобиль с массой 2т трогается с места и движется с ускорением 0,2м\с2. Чему равна сила тяги при разгоне автомобиля, если коэффициент трения 0.6?

Answer 1

Думаю как-то так:
На тело действуют четыре силы: N, Fтяг, Fтр., Fтяж.
Выполняется 2-ой закон Ньютона. Rвектр.=m*aвектр.
N+Fтяг+Fт+ Fтяж=m*a (у сил и уск. св. пад. векторы)
(OX):-Fтр+Fтяг=ma
Fтяг=m*a+мю*m*g
(OY):N-Fтяж=m*a
N=Fтяж => a=0 или m=0
Fтяг=m*a+ мю*m*g
Fтяг=2000 кг* 0.2 H\кг+2000 кг*0.6*10 H\кг=12400 H= 12,4кH

Answer 2

Calculation of the Traction Force

To calculate the traction force acting on the car during acceleration, we need to consider the forces involved. The main forces acting on the car are the gravitational force (weight) and the force of friction.

1. Gravitational Force (Weight): The weight of the car is equal to its mass multiplied by the acceleration due to gravity (9.8 m/s^2). In this case, the weight can be calculated as follows:

Weight = mass * acceleration due to gravity Weight = 2,000 kg * 9.8 m/s^2

2. Force of Friction: The force of friction opposes the motion of the car and depends on the coefficient of friction and the normal force. The normal force is equal to the weight of the car in this case.

Force of Friction = coefficient of friction * normal force

Since the car is accelerating, the normal force is equal to the weight of the car.

Now, let's calculate the traction force using the given information:

1. Weight: Weight = 2,000 kg * 9.8 m/s^2 = 19,600 N

2. Force of Friction: Force of Friction = 0.6 * 19,600 N = 11,760 N

Therefore, the traction force acting on the car during acceleration is 11,760 N.