Question

Тело массой 50 г подбросили вертикально вверх со скоростью 36км\ч.На какую высоту относительно точки броска поднимается тело ?

Answer 1

По закону сохр. энергии mgh=mv0²/2
h=v0²/2g=36²/20=64,8 м
h от массы тела не зависит.

Answer 2

36 км/ч=10 м/с. 
H= v v - vнач vнач/2g. 
H=0-100/-20=5 (м).

Answer 3

Calculation of the Height Reached by the Object

To calculate the height reached by the object, we can use the equations of motion. The initial velocity of the object is given as 36 km/h, which we need to convert to m/s.

Given: - Mass of the object (m) = 50 g = 0.05 kg - Initial velocity (u) = 36 km/h

To convert the initial velocity from km/h to m/s, we can use the conversion factor 1 km/h = 0.2778 m/s.

Converting the initial velocity: u = 36 km/h * 0.2778 m/s = 10 m/s

Using the equation for the final velocity (v) in vertical motion: v^2 = u^2 + 2as

Since the object is thrown vertically upwards, the final velocity (v) will be zero at the highest point. Therefore, we can rewrite the equation as: 0 = u^2 + 2as

Simplifying the equation: 2as = -u^2

The acceleration (a) in this case is equal to the acceleration due to gravity (g), which is approximately 9.8 m/s^2.

Substituting the values into the equation: 2 * 9.8 * s = -10^2

Simplifying further: 19.6s = -100

Solving for s (the height reached by the object): s = -100 / 19.6 ≈ -5.1 meters

Since the height cannot be negative, we take the absolute value of s: The object reaches a height of approximately 5.1 meters above the point of release.

Please note that the negative sign indicates the direction of motion, but we are only interested in the magnitude of the height reached.