Question

Газ при давление 0,2 ПА и температура 15° С имеет объем 5 м^3 чему равен объем газа массы газа при атмосферное давлении 100 кПа и температуре 0° С

Answer 1

P1V1/T1=P2V2/T2

V2=T2P1V1/T1P2 = 0.2*288*5/100000*273=1,7*10^-5 м³

Answer 2

Calculation of Gas Volume at Atmospheric Pressure and 0°C

To calculate the volume of gas at atmospheric pressure (100 kPa) and a temperature of 0°C, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in Pa) - V is the volume of the gas (in m^3) - n is the number of moles of gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

Given: - Pressure (P1) = 0.2 Pa - Temperature (T1) = 15°C = 15 + 273.15 = 288.15 K - Volume (V1) = 5 m^3

We need to find the volume (V2) at a pressure (P2) of 100 kPa and a temperature (T2) of 0°C = 0 + 273.15 = 273.15 K.

To find the number of moles (n) of gas, we can rearrange the ideal gas law equation:

n = PV / RT

Let's calculate the number of moles (n1) of gas at the initial conditions (P1, V1, T1):

n1 = (P1 * V1) / (R * T1)

Now, we can use the number of moles (n1) to find the volume (V2) at the final conditions (P2, T2):

V2 = (n1 * R * T2) / P2

Substituting the given values into the equations, we can calculate the volume (V2) of the gas at atmospheric pressure and