Question

В калориметр, содержащий лед массой 100 г при температуре 0 ° С, впустили пар, температура которой 100 ° С. Сколько воды окажется в калориметре после того, как весь лед растает?

Answer 1

Q=∧*m1
Q=L*m2+св*m2Δt
∧*m1=L*m2+св*m2Δt
∧*m1=m2*(L+cΔt)
m2=∧*m1/(L+cΔt)
m=m1+m2
m=100+12,5=112,5г

Answer 2

Calculation of the amount of water in the calorimeter after all the ice melts

To calculate the amount of water in the calorimeter after all the ice melts, we can use the principle of conservation of energy. The energy gained by the ice as it melts is equal to the energy lost by the steam as it condenses.

Let's denote the mass of the ice as m1 (100 g) and the temperature of the ice as t1 (0 °C). The mass of the steam is not given, so we'll denote it as m2. The temperature of the steam is given as t2 (100 °C).

According to the principle of conservation of energy, the energy gained by the ice as it melts is equal to the energy lost by the steam as it condenses. We can express this as an equation:

m1 * c * (0 - t1) = m2 * c * (t2 - 0)

Where: - c is the specific heat capacity of water (which is approximately 4.18 J/g°C).

Simplifying the equation, we get:

m1 * (-t1) = m2 * t2

Substituting the given values, we have:

100 g * (-0 °C) = m2 * 100 °C

Simplifying further, we find:

m2 = 100 g

Therefore, the mass of the steam is also 100 g.

Since the mass of the water remains constant throughout the process, the total mass of water in the calorimeter after all the ice melts is:

m1 + m2 = 100 g + 100 g = 200 g

Therefore, there will be 200 grams of water in the calorimeter after all the ice melts.