Question

Цепь состоит из двух последовательно соединенных проводников сопротивлениями R1=40 ОМ и R2=60 ОМ. Напряжение в цепи 2кВ. Найти общее сопротивление и силу тока в цепи, а также напряжение на каждом проводнике.

Answer 1

Rob=R1+R2=40+60=100 Ом
i=U/R=2000/100=20A
U1=R1*i=40*20=800V
U2=R2*i=60*20=1200V

Answer 2

Calculation of Total Resistance

To find the total resistance in the circuit, we need to add the resistances of R1 and R2, which are given as 40 Ω and 60 Ω respectively. The formula to calculate the total resistance in a series circuit is:

Total Resistance (R_total) = R1 + R2

Substituting the given values:

R_total = 40 Ω + 60 Ω = 100 Ω .

Calculation of Current

To calculate the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). The formula is:

Current (I) = Voltage (V) / Total Resistance (R_total)

Substituting the given values:

I = 2 kV / 100 Ω = 20 A .

Calculation of Voltage across Each Resistor

To calculate the voltage across each resistor, we can use Ohm's Law again. The voltage across a resistor is equal to the current flowing through it multiplied by its resistance. The formulas are:

Voltage across R1 (V1) = Current (I) * Resistance of R1 (R1)

Voltage across R2 (V2) = Current (I) * Resistance of R2 (R2)

Substituting the given values:

V1 = 20 A * 40 Ω = 800 V

V2 = 20 A * 60 Ω = 1200 V .

Therefore, the total resistance in the circuit is 100 Ω, the current flowing through the circuit is 20 A, and the voltage across R1 is 800 V, while the voltage across R2 is 1200 V.