Question

1.На чашке весов лежит алюминиевый брусок размером 2*5*10см.определитель силу,с которой брусок действует на чашку весов. 2.для получения сплава использовали 1800г меди и 730г олова.определитель плотность сплава .считайте,что объём сплава равен сумме объёмов меди и олова.срочно

Answer 1

Решение:
Переводим см в м:
V=abc
V=0,02м*0,05м*0,1м=0,0001 м3
Мы нашли объем V
m=pV
m= 2 700 кг/м3* 0,0001м3= 0,27 кг
P=mg
P= 0,27 кг* 10 Н/кг=2,7 Н
Ответ: P=2,7 Н

Answer 2

Determining the Force Exerted by the Aluminum Block on the Scale:

To determine the force exerted by the aluminum block on the scale, we need to calculate its weight. The weight of an object can be calculated using the formula:

Weight = Mass x Gravity

The mass of the aluminum block can be calculated using its density and volume. However, the density of the aluminum block is not provided in the question. Therefore, we cannot accurately determine the force exerted by the block on the scale without this information.

Determining the Density of the Alloy:

To determine the density of the alloy, we need to calculate its mass and volume. The mass of the alloy is given as 1800g of copper and 730g of tin. The volume of the alloy is assumed to be equal to the sum of the volumes of copper and tin.

To calculate the volume of the alloy, we need to know the densities of copper and tin. However, the densities of copper and tin are not provided in the question. Therefore, we cannot accurately determine the density of the alloy without this information.

In order to provide a more accurate answer, please provide the densities of aluminum, copper, and tin.