Question

Трамвай 6000кг движется со скоростью 36км/с2 после торможения трамвай остановился через 30с.Найдите силу торможения

Answer 1

M=6000 кг                          2-й закон Ньютона:
v₀=36 км/ч=20 м/с               F=ma=m(v-v₀)/t;
v=0                                       F=6000(0-20)/30= - 4000 H;
t=30 c                                 Ответ:  F= - 4000 H.
_______________
F-?

Answer 2

Calculation of Braking Force

To find the braking force, we need to use the equation:

Force = mass × acceleration

Given: - Mass of the tram: 6000 kg - Deceleration (negative acceleration) after braking: 36 km/s^2 - Time taken to stop: 30 s

First, we need to convert the deceleration from km/s^2 to m/s^2. Since 1 km = 1000 m and 1 hour = 3600 s, we can convert the deceleration as follows:

Deceleration = 36 km/s^2 × (1000 m/km) / (3600 s/hour) = 10 m/s^2

Now, we can calculate the braking force using the equation mentioned above:

Force = 6000 kg × (-10 m/s^2) = -60,000 N

Therefore, the braking force is -60,000 N.

Please note that the negative sign indicates that the force is acting in the opposite direction of motion, which is necessary to decelerate the tram.