Question

Кабина лифта массой 103 кг начинает подъем с ускорением 1 м/с2. Жесткость каната лифта равна 106 Н/м. Найдите удлинение каната в момент начала подъема.

Answer 1

F=k·Δl

F=ma

ma=k·Δl

Δl=(ma)/k

Δl=(103 · 1)/106 ≈ 0,9

ответ : ≈ 90 см

Answer 2

Calculation of Cable Elongation in the Moment of Lift Start

To calculate the elongation of the cable in the moment of lift start, we need to consider the mass of the elevator cabin, the acceleration, and the stiffness of the cable.

Given: - Mass of the elevator cabin (m): 103 kg - Acceleration (a): 1 m/s^2 - Stiffness of the cable (k): 106 N/m

To find the elongation of the cable, we can use Hooke's Law, which states that the elongation of a spring or cable is directly proportional to the force applied to it.

The force applied to the cable can be calculated using Newton's second law of motion: F = m * a, where F is the force, m is the mass, and a is the acceleration.

Let's calculate the force applied to the cable: F = m * a F = 103 kg * 1 m/s^2 F = 103 N

Now, we can use Hooke's Law to find the elongation of the cable: F = k * x, where F is the force, k is the stiffness of the cable, and x is the elongation of the cable.

Rearranging the equation, we can solve for x: x = F / k

Substituting the values: x = 103 N / 106 N/m x = 0.000097 m

Therefore, the elongation of the cable in the moment of lift start is approximately 0.000097 meters.

Please note that the search results provided by You.com did not contain relevant information for this specific calculation. The calculation was performed using the principles of physics and engineering.