Question

Нитяной маятник совершил 25 колебаний за 50 с. опредилите период и частоту колебаний.

Answer 1

N = 25,  t = 50 c

Период колебаний:

T = t/N = 50/25 = 2 c.

Частота колебаний:

n = 1/T = 0,5 Гц

Ответ: 2 с;  0,5 Гц.

Answer 2

частота => кол-во колебаний разделить на время=> 25:50=1:2 Гц.  период=1:частоту=1:(1:2)=2с

Answer 3

Calculation of Period and Frequency of a Pendulum

To determine the period and frequency of a pendulum, we need to know the number of oscillations and the time it takes to complete those oscillations.

In this case, the pendulum completed 25 oscillations in 50 seconds.

Period of the Pendulum

The period of a pendulum is the time it takes for one complete oscillation. It can be calculated by dividing the total time by the number of oscillations.

To find the period of the pendulum in this case, we divide the total time of 50 seconds by the number of oscillations, which is 25:

Period = Total Time / Number of Oscillations

Period = 50 seconds / 25 oscillations

Calculating this, we find:

Period = 2 seconds

Therefore, the period of the pendulum is 2 seconds.

Frequency of the Pendulum

The frequency of a pendulum is the number of oscillations it completes in one second. It is the reciprocal of the period and can be calculated by dividing the number of oscillations by the total time.

To find the frequency of the pendulum in this case, we divide the number of oscillations, which is 25, by the total time of 50 seconds:

Frequency = Number of Oscillations / Total Time

Frequency = 25 oscillations / 50 seconds

Calculating this, we find:

Frequency = 0.5 Hz

Therefore, the frequency of the pendulum is 0.5 Hz.

In summary, the pendulum in question has a period of 2 seconds and a frequency of 0.5 Hz.