Question

Рымкевич. В некоторой точке поля на заряд 2 нКл действует сила 0, 4 мкН. Найти напряженность поля в этой точке.

Answer 1

Ищем напряженность по формулы Е=F/q, где:
Е - напряженность
F -сила
q - заряд
Е =  0,4*10^(-6)/2*10^(-9)=0,2*10^3=200Н/Кл

Answer 2

По формуле напряжености поля E=F/Q
E=0,4*10 в минус 6 ой разделить на 2*10 в минус 9 ой=200В

Answer 3

Calculation of Electric Field Intensity

To find the electric field intensity at a certain point in a field, we can use the formula:

E = F / q

Where: - E is the electric field intensity, - F is the force acting on the charge, and - q is the magnitude of the charge.

In this case, we are given that a force of 0.4 μN (micro-newtons) is acting on a charge of 2 nC (nano-coulombs).

Substituting the given values into the formula, we can calculate the electric field intensity:

E = (0.4 μN) / (2 nC)

Converting the units to SI units: - 1 μN = 10^-6 N - 1 nC = 10^-9 C

E = (0.4 x 10^-6 N) / (2 x 10^-9 C)

Simplifying the expression: E = 0.2 x 10^3 N/C

Therefore, the electric field intensity at the given point is 0.2 x 10^3 N/C.

Please note that the above calculation is based on the given information and the formula for electric field intensity.