Question

"в сосуд поместили 2 кг воды температурой 50 градусов и 5 кг льда при температуре -40 градусов какая температура установится в сосуде"

Answer 1

"в сосуд поместили m1= 2 кг воды температурой t1=50 градусов
и m2=5 кг льда при температуре t2=-40 градусов какая температура установится в
сосуде"

Сделаем оценку
1)сколько тепла может отдать вода при остывании до 0
Q1=c*m1*(t1-0)=4200*2*50=420000 Дж
2)Сколько тепла надо для нагревания льда
Q2=c2*m2*(0-t2)=2100*5*40=420000 Дж

Легко заметить что Q1=Q2
Это значит что процесс плавления не начнется и лед прогреется до 0С
а вода остынет до нуля градусов

Ответ t=0C - конечная температура

Answer 2

Calculation of Final Temperature

To calculate the final temperature in the vessel, we can use the principle of conservation of energy. The total heat gained by the water and ice will be equal to the total heat lost by the water and ice.

Let's denote: - m1 as the mass of water (2 kg) - t1 as the initial temperature of water (50 degrees Celsius) - m2 as the mass of ice (5 kg) - t2 as the initial temperature of ice (-40 degrees Celsius) - T as the final temperature of the mixture

The heat gained by the water can be calculated using the formula: Q1 = m1 * c1 * (T - t1), where c1 is the specific heat capacity of water.

The heat gained by the ice can be calculated using the formula: Q2 = m2 * c2 * (T - t2), where c2 is the specific heat capacity of ice.

Since the heat gained and lost are equal, we can set up the equation: Q1 = -Q2.

Now, let's find the specific heat capacities of water and ice.

According to the search result snippet from we have: - m1 = 2 kg - t1 = 5 - m2 = 5 - t2 = 40

Using this information, we can calculate the final temperature T.

Calculation Steps:

1. Calculate the heat gained by the water: Q1 = m1 * c1 * (T - t1) 2. Calculate the heat gained by the ice: Q2 = m2 * c2 * (T - t2) 3. Set up the equation: Q1 = -Q2 4. Solve the equation for T.

Let's proceed with the calculations.