Question

Определите Мощность трамвая к концу 8-й секунды после начала движения, если он развил к этому моменту скорость 36 км/ч Масса трамвая 10т

Answer 1

N=A/t=500000/8=62500[Вт]=62,5[кВт]            A=F*S=12500*40=500000[Дж]      
F=m*a=10000*1,25=12500[H]    
Т.к. Vo=0м/с     a= V/t=10/8=1.25[м/с^2] 
 S= (V^2)2a =10*10/2*1,25=40[м]

Answer 2

Calculation of Tram Power

To calculate the power of a tram at the end of the 8th second after starting its motion, we need to use the formula:

Power = Force × Velocity

Given information: - Velocity of the tram = 36 km/h - Mass of the tram = 10 tons

First, we need to convert the velocity from km/h to m/s: - 36 km/h = 36,000 m/3,600 s = 10 m/s

Next, we need to calculate the force acting on the tram. To do this, we can use Newton's second law of motion:

Force = Mass × Acceleration

Since we are given the mass of the tram (10 tons), we need to convert it to kilograms: - 1 ton = 1000 kg - 10 tons = 10,000 kg

Now, we need to find the acceleration of the tram. We can use the following equation of motion:

Velocity = Initial Velocity + (Acceleration × Time)

Rearranging the equation, we get:

Acceleration = (Velocity - Initial Velocity) / Time

Since the tram starts from rest, the initial velocity is 0 m/s. The time is 8 seconds.

Substituting the values into the equation: - Acceleration = (10 m/s - 0 m/s) / 8 s = 1.25 m/s²

Now, we can calculate the force: - Force = Mass × Acceleration = 10,000 kg × 1.25 m/s² = 12,500 N

Finally, we can calculate the power: - Power = Force × Velocity = 12,500 N × 10 m/s = 125,000 W

Therefore, the power of the tram at the end of the 8th second after starting its motion is 125,000 Watts.