Question

Резиновый шнур под действием силы 15 н удлинился на 3 см. Определить жесткость шнура

Answer 1

F=kx
k=F/x
k= 15 Н/0,03м = 500 н/м

Answer 2

Calculation of the Stiffness of a Rubber Cord

To determine the stiffness of a rubber cord, we can use Hooke's Law, which states that the force exerted on a spring-like object is directly proportional to the displacement of the object from its equilibrium position. In this case, the rubber cord is acting like a spring.

According to the information provided, the rubber cord elongated by 3 cm under the influence of a force of 15 N. We can use this information to calculate the stiffness of the cord.

Hooke's Law can be expressed as:

F = kx

Where: - F is the force applied to the cord (15 N in this case) - k is the stiffness constant (to be determined) - x is the displacement of the cord (3 cm or 0.03 m in this case)

To find the stiffness constant (k), we rearrange the equation:

k = F / x

Substituting the given values:

k = 15 N / 0.03 m

Calculating the value:

k = 500 N/m

Therefore, the stiffness of the rubber cord is 500 N/m.