Question

Мотоциклист разогнался с места до 90 км/ч за 10 сек. Определить ускорение и путь.

Answer 1

Ускорение = 2,5 м/с в квадрате по формуле а= v-v0/t 
путь равен 135 м  по формуле s= t+ at в квадрате/ 2   т.к. разгонялся с места, то скорость начальная = 0 и мы ее не учитываем

Answer 2

Calculation of Acceleration and Distance

To determine the acceleration and distance traveled by the motorcyclist, we can use the formula:

Acceleration (a) = Change in velocity (v) / Time taken (t)

Given that the motorcyclist accelerated from 0 km/h to 90 km/h in 10 seconds, we can convert the velocities to meters per second (m/s) for consistency:

Initial velocity (u) = 0 km/h = 0 m/s Final velocity (v) = 90 km/h = 25 m/s Time taken (t) = 10 seconds

Using the formula, we can calculate the acceleration:

Acceleration (a) = (v - u) / t

Substituting the values:

Acceleration (a) = (25 m/s - 0 m/s) / 10 s = 2.5 m/s^2 The acceleration of the motorcyclist is 2.5 m/s^2.

To calculate the distance traveled, we can use the formula:

Distance (s) = Initial velocity (u) * Time taken (t) + 0.5 * Acceleration (a) * (Time taken (t))^2

Substituting the values:

Distance (s) = 0 m/s * 10 s + 0.5 * 2.5 m/s^2 * (10 s)^2 = 0 m + 0.5 * 2.5 m/s^2 * 100 s^2 = 125 m

The motorcyclist traveled a distance of 125 meters during the acceleration period.