Question

На дне шахты высота ртутного столбика в ртутном барометре равна 80 см. Найдите давление воздуха в шахте (ответ выразите в килопаскалях).

Answer 1

1 мм рт.ст=133,2
80 см=800м
133,2*800=106560Па=106,56кПа

Answer 2

Calculation of Air Pressure in the Mine

To calculate the air pressure in the mine, we can use the height of the mercury column in the mercury barometer. The height of the mercury column is given as 80 cm.

The pressure exerted by a column of liquid is given by the equation:

P = ρgh

Where: - P is the pressure - ρ is the density of the liquid - g is the acceleration due to gravity - h is the height of the column

In this case, the liquid is mercury, which has a density of approximately 13,600 kg/m³ The acceleration due to gravity is approximately 9.8 m/s².

Converting the height of the mercury column from centimeters to meters, we have:

h = 80 cm = 0.8 m

Substituting the values into the equation, we can calculate the pressure:

P = (13,600 kg/m³) * (9.8 m/s²) * (0.8 m)

Calculating this expression gives us the pressure in pascals (Pa). To convert the pressure to kilopascals (kPa), we divide the result by 1000:

P = ((13,600 kg/m³) * (9.8 m/s²) * (0.8 m)) / 1000 kPa

Now, let's calculate the pressure:

P = (13,600 * 9.8 * 0.8) / 1000 kPa

Using a calculator, we find that the air pressure in the mine is approximately 107.07 kPa.

Please note that this calculation assumes that the density of mercury and the acceleration due to gravity are constant throughout the mine. Additionally, this calculation does not take into account any other factors that may affect the air pressure in the mine.