Question

Длина пружины к которой подвешено тело массой m1= 4 ко равна l1= 0.30 м. если к ней подвесить ещё одно тело массой m2 = 3 кг то длина пружины станет равной l2 = 0.36. на сколько увеличилась потенциальная энергия пружины после подвешивания второго груза?

Answer 1

Определим коэффициент жесткости пружины
F=k*dx
30=k*0.06
k=500 Н/м
Энергия пружины равна
E=k*dx²/2
E=500*0.06²/2=0.9 Дж

Answer 2

Calculation of Potential Energy Increase

To calculate the increase in potential energy of the spring after hanging the second mass, we can use the formula for potential energy in a spring:

Potential energy (PE) = 0.5 * k * (l2^2 - l1^2)

Where: - PE is the potential energy of the spring - k is the spring constant - l1 is the initial length of the spring - l2 is the final length of the spring

Given the following information: - Mass of the first object (m1) = 4 kg - Initial length of the spring (l1) = 0.30 m - Mass of the second object (m2) = 3 kg - Final length of the spring (l2) = 0.36 m

We need to find the spring constant (k) to calculate the potential energy increase. Unfortunately, the spring constant is not provided in the given information. Without the spring constant, we cannot accurately calculate the potential energy increase.

Please provide the spring constant (k) or any additional information to proceed with the calculation.