Question

Тело массой 1 кг свободно падает с высоты 10 метров и подлетает к земле со скоростью 10 м/с. Определите работу сил сопротивления воздуха, действующих на тело

Answer 1

A = Ек - Eп. ;
Ек = mV^2/2 = 1*10^2 = 50Дж;
Еп. = mgh = 1*10*10 = 100Дж;
A = 50 - 100 = -50Дж.

Answer 2

Calculation of Work Done by Air Resistance

To determine the work done by air resistance on the falling object, we need to consider the change in kinetic energy of the object as it falls from a height of 10 meters and reaches the ground with a velocity of 10 m/s.

The work done by air resistance can be calculated using the following formula:

Work = Change in Kinetic Energy

The change in kinetic energy can be calculated using the formula:

Change in Kinetic Energy = (1/2) * mass * (final velocity^2 - initial velocity^2)

Given: - Mass of the object (m) = 1 kg - Initial velocity (u) = 0 m/s (since the object is freely falling) - Final velocity (v) = 10 m/s

Substituting these values into the formula, we can calculate the change in kinetic energy:

Change in Kinetic Energy = (1/2) * 1 kg * (10 m/s)^2 - (0 m/s)^2

Simplifying the equation, we get:

Change in Kinetic Energy = (1/2) * 1 kg * 100 m^2/s^2

Now, we can calculate the work done by air resistance, which is equal to the change in kinetic energy:

Work = (1/2) * 1 kg * 100 m^2/s^2

Simplifying the equation, we get:

Work = 50 Joules

Therefore, the work done by air resistance on the falling object is 50 Joules.