Question

Какое количество энергии выделит вода массой 2 кг при охлаждении от 100 градусов до 0 градусов? Какое количество энергии вы делится, если вместо воды взять столько же пара при 100 градусах?

Answer 1

Q=cm*100=4200*2кг*100=840000ДЖ.
Q=лямда * массу

Answer 2

Calculation for the amount of energy released by cooling water from 100 degrees Celsius to 0 degrees Celsius:

To calculate the amount of energy released when cooling water from 100 degrees Celsius to 0 degrees Celsius, we can use the formula:

Q = m * c * ΔT

Where: - Q is the amount of energy released (in joules) - m is the mass of the water (in kilograms) - c is the specific heat capacity of water (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Given that the mass of the water is 2 kg and the change in temperature is from 100 degrees Celsius to 0 degrees Celsius, we can substitute these values into the formula.

The specific heat capacity of water is approximately 4.186 joules per gram per degree Celsius, which is equivalent to 4186 joules per kilogram per degree Celsius.

Substituting the values into the formula:

Q = 2 kg * 4186 J/kg°C * (0°C - 100°C)

Calculating the expression:

Q = 2 kg * 4186 J/kg°C * (-100°C)

Q = -836,000 J

Therefore, the amount of energy released by cooling 2 kg of water from 100 degrees Celsius to 0 degrees Celsius is -836,000 joules.

Calculation for the amount of energy released by cooling an equal mass of steam at 100 degrees Celsius:

To calculate the amount of energy released when cooling an equal mass of steam at 100 degrees Celsius, we can use the same formula:

Q = m * c * ΔT

However, we need to consider that steam at 100 degrees Celsius is in the gaseous state, while water at 0 degrees Celsius is in the liquid state. The specific heat capacity of steam is different from that of water.

The specific heat capacity of steam is approximately 2.03 joules per gram per degree Celsius, which is equivalent to 2030 joules per kilogram per degree Celsius.

Substituting the values into the formula:

Q = 2 kg * 2030 J/kg°C * (0°C - 100°C)

Calculating the expression:

Q = 2 kg * 2030 J/kg°C * (-100°C)

Q = -406,000 J

Therefore, the amount of energy released by cooling 2 kg of steam from 100 degrees Celsius to 0 degrees Celsius is -406,000 joules.

Please note that the negative sign indicates the release of energy during the cooling process.