Question

К неподвижному телу массой 20 кг приложили постоянную силу 60 Н.Какой путь пройдёт это тело за 12 с?

Answer 1

Второй закон Ньютона: F = am 
Находим а: a = F/m = 60 H / 20 кг = 3 м/c^2 (метр в секунду в квадрате) 
S = V0*t + a*t^2/2 (Начальная скорость умн. на время + ускорение * время в квадрате и пополам) 
Так как начальная скорость равна нулю: 
S = a*t*t/2 = 3*12*12/2 = 216 м

Answer 2

Calculation of the Distance Traveled by a Body

To calculate the distance traveled by a body when a constant force is applied to it, we can use the equation s = vt, where s represents the distance, v represents the velocity, and t represents the time.

In this case, a constant force of 60 N is applied to a body with a mass of 20 kg. We need to find the distance traveled by the body in 12 seconds.

To calculate the distance, we first need to find the acceleration of the body using Newton's second law of motion, which states that F = ma, where F is the force, m is the mass, and a is the acceleration.

Given that the force applied is 60 N and the mass of the body is 20 kg, we can calculate the acceleration as follows:

a = F/m = 60 N / 20 kg = 3 m/s^2.

Now that we have the acceleration, we can calculate the velocity of the body using the equation v = at, where v is the velocity, a is the acceleration, and t is the time.

Given that the time is 12 seconds and the acceleration is 3 m/s^2, we can calculate the velocity as follows:

v = at = 3 m/s^2 * 12 s = 36 m/s.

Finally, we can calculate the distance traveled by the body using the equation s = vt, where s is the distance, v is the velocity, and t is the time.

Given that the time is 12 seconds and the velocity is 36 m/s, we can calculate the distance as follows:

s = vt = 36 m/s * 12 s = 432 meters.

Therefore, the body will travel a distance of 432 meters in 12 seconds when a constant force of 60 N is applied to it.

Answer

The body will travel a distance of 432 meters in 12 seconds when a constant force of 60 N is applied to it.