Question

Під дією сили 4Н пружина видовжилася на 2см.Яка жосткість пружини?

Answer 1

По формуле  f=kx/2(x в квадрате)
 см нужно перевести в метры =0.02 м
k=f2/x(x  в квадрате);k=4*2/0,02*2 ;k=200000 н/м

Answer 2

Calculation of the Spring Constant

To determine the spring constant of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

Where: - F is the force applied to the spring (in Newtons) - k is the spring constant (in Newtons per meter) - x is the displacement of the spring (in meters)

In this case, we are given that a force of 4 N caused the spring to elongate by 2 cm (or 0.02 m). We can use this information to calculate the spring constant.

F = 4 N x = 0.02 m

Substituting these values into Hooke's Law, we can solve for the spring constant:

4 N = k * 0.02 m

To isolate k, we divide both sides of the equation by 0.02 m:

k = 4 N / 0.02 m

Simplifying the equation gives us:

k = 200 N/m

Therefore, the spring constant of the given spring is 200 N/m.