Question

Стрела,выпущенная из лука вертикально вверх,приобрела максимальную потенциальную энергию 20 Дж. Найдите Массу стрелы,если известно,что она поднялась на высоду 25м.

Answer 1

Дано
Ep=20дж
h=25м
g=10м/c^2
Формула
Ep=mgh m=Ep/gh=20/250=0.08кг

Answer 2

Calculation of the Mass of the Arrow

To find the mass of the arrow, we can use the principle of conservation of mechanical energy. The potential energy gained by the arrow when it reaches its maximum height is equal to the initial potential energy when it was released from the bow.

The potential energy of an object is given by the equation:

Potential Energy = mass x gravity x height

Given that the arrow gained a maximum potential energy of 20 J and reached a height of 25 m, we can set up the equation as follows:

20 J = mass x 9.8 m/s^2 x 25 m

Simplifying the equation, we can solve for the mass of the arrow:

mass = 20 J / (9.8 m/s^2 x 25 m)

Calculating the mass using the given values:

mass = 20 J / (245 m^2/s^2)

mass ≈ 0.0816 kg

Therefore, the mass of the arrow is approximately 0.0816 kg.