Question

РЕШИТЕ! БУДУ БЛАГОДАРНА! Найдите жесткость пружины , которая под действием силы, модуль которой F=6,0 Н, УДЛИНИЛАСЬ НА дельта L =40 СМ

Answer 1

F=kl
6=0.4k
6\0.4=k

6\0.4=15                 

Answer 2

Calculation of Spring Stiffness

To find the stiffness of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement or elongation of the spring. Mathematically, this can be expressed as:

F = k * ΔL

Where: - F is the force applied to the spring (6.0 N in this case) - k is the stiffness or spring constant - ΔL is the change in length of the spring (40 cm in this case)

To find the stiffness of the spring, we need to rearrange the equation to solve for k:

k = F / ΔL

Substituting the given values:

k = 6.0 N / 40 cm

Now, we need to convert the length from centimeters to meters, as the SI unit for force is Newtons and the SI unit for length is meters:

k = 6.0 N / 0.4 m

Simplifying the expression:

k = 15 N/m

Therefore, the stiffness of the spring is 15 N/m.