Question

В баллоне вместимостью 45л хранится кислород под давлением 1,52МПа при температуре 27°С.Какой обьем занял бы этот газ при нормальных условиях? Какова его масса. Подробное решение

Answer 1

Если при норм условиях, температура= 0 градусов и давление 100 000 Па то ответ будет таким...

Answer 2

Calculation of Volume at Normal Conditions

To calculate the volume of the gas at normal conditions, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas in Kelvin

In this case, we have the following information: - P = 1.52 MPa - V = 45 L - T = 27°C

To convert the temperature from Celsius to Kelvin, we add 273.15: T = 27°C + 273.15 = 300.15 K

Now we can rearrange the ideal gas law equation to solve for V:

V = (nRT) / P

To find the number of moles of the gas, we can use the equation:

n = PV / RT

Substituting the given values into the equation:

n = (1.52 MPa * 45 L) / (8.314 J/(mol·K) * 300.15 K)

Now we can calculate the number of moles:

n = (1.52 * 10^6 Pa * 45 * 10^-3 m^3) / (8.314 J/(mol·K) * 300.15 K)

n = 0.0867 mol

Substituting the value of n back into the equation for V:

V = (0.0867 mol * 8.314 J/(mol·K) * 300.15 K) / (1.52 * 10^6 Pa)

Now we can calculate the volume at normal conditions:

V = 0.0867 mol * 8.314 J/(mol·K) * 300.15 K / 1.52 * 10^6 Pa

V ≈ 0.0045 m^3 or 4.5 L

Therefore, the volume of the gas at normal conditions would be approximately 4.5 liters.

Calculation of Mass of the Gas

To calculate the mass of the gas, we can use the equation:

m = n * M

Where: - m is the mass of the gas - n is the number of moles of the gas - M is the molar mass of the gas

The molar mass of oxygen (O2), which is the main component of air, is approximately 32 g/mol.

Substituting the values into the equation:

m = 0.0867 mol * 32 g/mol

m ≈ 2.77 g

Therefore, the mass of the gas would be approximately 2.77 grams.

Please note that the calculations above assume ideal gas behavior and do not take into account any deviations from ideal conditions.