Question

Эскалатор метро движется со скоростью 80 м/с. Найдите время за которое пассажир переместится на 64 м относительно земли, если он сам идет в направлении движения со скоростью 0,2 м/с в системе отчета, связанной с эскалатором.

Answer 1

ОПЕЧАТКА! 
Скорость, конечно, 80 см/с. Ну не может эскалатор двигаться со скоростью 300 км/ч

Имеем:
Переносная скорость:
V₁ = 0,80 м/с
Относительная скорость:
V₂ = 0,20 м/с

Абсолютная скорость:
V = V₁+V₂ = 0,80+0,20 = 1 м/с

Искомое время
t = S/V = 64/1 = 64 c    или 1 мин 4 сек

Answer 2

Calculation of Time for Passenger to Move 64m Relative to the Ground

To find the time it takes for a passenger to move 64m relative to the ground while walking in the direction of the escalator's movement, we can use the concept of relative velocity.

The relative velocity of the passenger with respect to the ground is the difference between the velocity of the passenger and the velocity of the escalator.

Given: - Velocity of the escalator (v_escalator) = 80 m/s - Velocity of the passenger (v_passenger) = 0.2 m/s

The relative velocity (v_relative) can be calculated as:

v_relative = v_passenger - v_escalator

Substituting the given values:

v_relative = 0.2 m/s - 80 m/s

Simplifying:

v_relative = -79.8 m/s

The negative sign indicates that the passenger is moving in the opposite direction of the escalator's movement.

Now, we can calculate the time it takes for the passenger to move 64m relative to the ground using the formula:

time = distance / velocity

Substituting the given distance (64m) and the relative velocity (-79.8 m/s):

time = 64m / (-79.8 m/s)

Calculating the result:

time ≈ -0.802 seconds

Since time cannot be negative, we can conclude that the passenger will not be able to move 64m relative to the ground in the direction of the escalator's movement while walking at a speed of 0.2 m/s.

Please note that the negative time value indicates that the passenger will not be able to reach the desired position.