Question

ПОМАГИТЕ ПОЖАЛУЙСТА РЕШИТЬ:перемещая заряд в первом проводнике ,электрическое поле совершает работу 20 Дж при меремещении такого же в этом проводнике электрического поле совершает работу 40 Дж .отношение напряжение U1/U2 на концах проводника равно в двух случаях

Answer 1

A1=q*U1
A2=q*U2
A1/A2=U1/U2=20/40=1/2
Ответ U1/U2=1/2

Answer 2

Calculation of Voltage Ratios

To solve this problem, we need to calculate the voltage ratios in two different scenarios. Let's denote the voltage in the first conductor as U1 and the voltage in the second conductor as U2.

Given: - Work done by the electric field when moving a charge in the first conductor = 20 J - Work done by the electric field when moving the same charge in the second conductor = 40 J

We know that the work done by the electric field is equal to the product of the charge and the potential difference (voltage). Mathematically, it can be expressed as:

Work = Charge * Voltage

In the first conductor, the work done is 20 J, and in the second conductor, the work done is 40 J. Let's assume the charge moved is the same in both cases.

Using the equation above, we can write the following equations:

20 J = Charge * U1 ---- (Equation 1) 40 J = Charge * U2 ---- (Equation 2)

To find the ratio U1/U2, we can divide Equation 1 by Equation 2:

(20 J)/(40 J) = (Charge * U1)/(Charge * U2)

Simplifying the equation, we get:

1/2 = U1/U2

Therefore, the ratio of the voltages U1/U2 in the two cases is 1/2.

Please let me know if you need any further clarification or assistance!