Question

Под действием силы 550 Н тело упруго деформировалось и его длина изменилась на 30 мм. Определите коэффициент жесткости.

Answer 1

F=kx, отсюда k=F/x=550/0,03=18333 н/м

Answer 2

Calculation of the Spring Constant

To determine the spring constant, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

Where: - F is the force applied to the spring (550 N in this case) - k is the spring constant (what we need to find) - x is the displacement of the spring (30 mm in this case)

Rearranging the equation, we can solve for the spring constant:

k = F / x

Substituting the given values:

k = 550 N / 30 mm

To ensure consistent units, we need to convert millimeters to meters:

k = 550 N / (30 mm * 0.001 m/mm)

Simplifying the equation:

k = 550 N / 0.03 m

Calculating the value:

k ≈ 18,333.33 N/m

Therefore, the spring constant is approximately 18,333.33 N/m.