Question

С каким ускорением движется вниз лифт если вес пасажира в нем уменьшился на 1/4?

Answer 1

С каким ускорением движется вниз лифт если вес пасажира в нем уменьшился на 1/4?
Дано Po=m*q  P=3*Po/4   a - ?

P= m*g - m*a
m*a=m*g-3*m*g/4
a=1*g/4=10/4=2,5 м/с2

Ответ a=2,5 м/с2

Answer 2

Человек стал давить на пол с силой F = 0.75 mg

то есть ускорение а = g - 0.75 g = g/4 = 2.5  м/с**2

Answer 3

Calculation of the Acceleration of the Elevator

To calculate the acceleration of the elevator when the weight of the passenger inside it decreases by 1/4, we need to consider the forces acting on the elevator.

The weight of the passenger can be expressed as the product of the mass of the passenger (m) and the acceleration due to gravity (g). When the weight decreases by 1/4, it means the new weight is 3/4 of the original weight.

Let's assume the original weight of the passenger is W. Therefore, the new weight of the passenger is (3/4)W.

The net force acting on the elevator is the difference between the weight of the passenger and the force exerted by the elevator to counteract it. This net force is equal to the product of the mass of the elevator (M) and its acceleration (a).

Using Newton's second law of motion, we can write the equation:

Net force = (3/4)W - Mg = Ma

Simplifying the equation, we get:

(3/4)W - Mg = Ma

To find the acceleration (a), we can rearrange the equation as follows:

a = (3/4)g - (3/4)(W/M)

Now, we can substitute the known values of g, W, and M to calculate the acceleration.

Please provide the values of g, W, and M so that I can calculate the acceleration for you.