Question

Масса углекислого газа объемом 1.5 м3 равна 6.5 кг определить плотность и удельный объем углекислого газа при этих условиях

Answer 1

Плотность=m/V
Плотность=6.5кг/1.5м=4 1/3

Answer 2

Calculation of Density and Specific Volume of Carbon Dioxide

To determine the density and specific volume of carbon dioxide at the given conditions, we need to use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (assumed to be constant) - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas (assumed to be constant)

Since we are given the volume of the gas (V = 1.5 m^3) and the mass of the gas (m = 6.5 kg), we need to calculate the number of moles of carbon dioxide.

To calculate the number of moles, we can use the formula:

n = m / M

Where: - m is the mass of the gas - M is the molar mass of carbon dioxide

The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Let's calculate the number of moles of carbon dioxide:

n = 6.5 kg / 44.01 g/mol

Now, we can substitute the values into the ideal gas law equation to calculate the density and specific volume.

Calculation Steps:

1. Convert the mass of carbon dioxide from kilograms to grams: - 6.5 kg = 6500 g

2. Calculate the number of moles of carbon dioxide: - n = 6500 g / 44.01 g/mol

3. Substitute the values into the ideal gas law equation: - PV = nRT - P * 1.5 m^3 = (6500 g / 44.01 g/mol) * R * T

To calculate the density and specific volume, we need additional information about the pressure and temperature of the gas. Please provide the values for pressure and temperature so that we can complete the calculation.