Question

Найти ёмкость плоского конденсатора.состоящего из двух круглых пластин диаметром 20 см(s=D^2*п/4),разделенных парафиновой пластинкой толщиной 1 мм( проницаемость парафина 2.1)

Answer 1

S=3,14*400/2=628 см2=628*10^-4 м2
С=e0*e*S/d=8,85*10^-12*628*10^-4*2.1/10^-3=11,67*10^-10 Ф 

Answer 2

Finding the Capacitance of a Flat Capacitor with Circular Plates

To find the capacitance of a flat capacitor consisting of two circular plates separated by a paraffin plate, we can use the formula for the capacitance of a parallel plate capacitor:

C = (ε₀ * A) / d

Where: - C is the capacitance - ε₀ is the vacuum permittivity (8.854 x 10^-12 F/m) - A is the area of one of the circular plates - d is the distance between the plates

In this case, the area of each circular plate can be calculated using the formula for the area of a circle:

A = π * (D/2)^2

Where: - A is the area - D is the diameter of the circular plate

The distance between the plates is given as the thickness of the paraffin plate, which is 1 mm.

Now, let's calculate the capacitance of the capacitor.

Calculation:

Given: - Diameter of the circular plates (D) = 20 cm = 0.2 m - Thickness of the paraffin plate (d) = 1 mm = 0.001 m - Permittivity of paraffin (ε) = 2.1 (dimensionless)

First, let's calculate the area of one circular plate:

A = π * (D/2)^2

A = π * (0.2/2)^2

A = π * (0.1)^2

A = 0.01π m^2

Now, let's calculate the capacitance using the formula:

C = (ε₀ * A) / d

C = (8.854 x 10^-12 F/m * 0.01π m^2) / 0.001 m

C = 8.854 x 10^-10π F

Using the value of π as approximately 3.14159, we can calculate the capacitance:

C ≈ 2.775 x 10^-9 F

Therefore, the capacitance of the flat capacitor with circular plates, separated by a paraffin plate, is approximately 2.775 nanofarads.

Please note that the value of the permittivity of paraffin used in this calculation is an approximation. The actual value may vary depending on the specific type and composition of the paraffin used.