Question

Шар массой 2кг плавает в воде. Каков V погруженной части шара?

Answer 1

Вес шара  P = mg = 2*10 = 20 (Н)

Так как шар плавает в воде, то его вес уравновешен выталкивающей силой, численно равной весу воды в объеме погруженной части шара, т.е.:
                   P = Fa = ρgV₁    =>    V₁ = P/ρg = 20:10000 = 0,002 (м³) = 2 (дм³)

Ответ: объем погруженной части шара 2 дм³ или 2 литра.

Answer 2

Calculating the Volume of the Submerged Sphere

To calculate the volume of the submerged part of the sphere, we can use the formula for buoyancy, which is given by:

V = m/ρg

Where: - V is the volume of the submerged part of the sphere - m is the mass of the sphere - ρ is the density of the fluid (in this case, water) - g is the acceleration due to gravity

Using the given information that the mass of the sphere is 2kg and it is floating in water, we can calculate the volume of the submerged part of the sphere.

Applying the Formula

Given: - m = 2kg - ρ = density of water - g = acceleration due to gravity

We can use the density of water and the acceleration due to gravity to calculate the volume of the submerged part of the sphere.

Calculating the Volume

Using the formula V = m/ρg, we can calculate the volume of the submerged part of the sphere. The density of water and the acceleration due to gravity are constants, so we can use their standard values in the calculation.

V = m/ρg

Now, let's calculate the volume using the given values and the standard values for the density of water and the acceleration due to gravity.

V = 2kg / (1000 kg/m^3 * 9.81 m/s^2)

V ≈ 0.000203 m^3

Therefore, the volume of the submerged part of the sphere is approximately 0.000203 m^3.