Question

Дерево брус 2х3х5 опустили в керосин.Определите выталкивающую силу.брусаа

Answer 1

 Дано:
V=30 м3
плотность=800 кг/м3
g=10 Н/кг
Fa-?
Решение:
Fa(выталкивающая сила или Архимедова сила)=800*30*10=240000 Н=240кН

Answer 2

Determining the Buoyant Force on the Wooden Beam

To determine the buoyant force acting on the wooden beam submerged in kerosene, we can use the principle of Archimedes' buoyant force. The buoyant force is equal to the weight of the fluid displaced by the object. In this case, the kerosene exerts an upward force on the wooden beam, which is equal to the weight of the kerosene displaced by the beam.

Calculation of the Buoyant Force

The buoyant force can be calculated using the formula:

Buoyant force = weight of the fluid displaced

The weight of the fluid displaced can be calculated using the formula:

Weight of the fluid displaced = volume of the fluid displaced × density of the fluid × acceleration due to gravity

Given that the dimensions of the wooden beam are 2x3x5, we can calculate the volume of the wooden beam and then use the density of kerosene to determine the buoyant force.

Calculation Steps

1. Calculate the Volume of the Wooden Beam: - Volume = length × width × height - Volume = 2 * 3 * 5 = 30 cubic units

2. Determine the Density of Kerosene: - The density of kerosene is approximately 0.8 g/cm³ or 800 kg/m³.

3. Calculate the Weight of the Fluid Displaced: - Weight of the fluid displaced = volume of the fluid displaced × density of the fluid × acceleration due to gravity - Weight of the fluid displaced = 30 * 800 * 9.81 = [235,440 N](https://www.engineeringtoolbox.com/kerosene-d_151.html)

Therefore, the buoyant force acting on the wooden beam submerged in kerosene is approximately 235,440 Newtons.

This calculation assumes that the wooden beam is fully submerged in the kerosene and that the kerosene exerts a uniform pressure on all parts of the beam.