Question

В алюминевый калориметр массой 100гв котором было 200г воды температура которой составляла 10 градусов положили медный брусок массой 150 г температура которога 100 градусов

Answer 1

Дано:
М (воды)=200г=0,2 кг
t(воды)=20(градусов)
С=4200 жд/кг*(градус цельсия)
М(бруска)=150г=0,15кг
t(бруска)=100(градусов цельсия)
С=400дж/кг*(градус Цельсия)
Найти:
t смеси

Решение:
Q=t*m*c
Q(воды)=0,2*20*4200=16800дж воды
Q(бруска)=400*0,15*100=6900 дж бруска

Answer 2

Calculation of Final Temperature

To calculate the final temperature of the system after the copper block is added to the aluminum calorimeter, we can use the principle of conservation of energy. The heat lost by the copper block will be equal to the heat gained by the aluminum calorimeter and the water it contains.

The heat lost by the copper block can be calculated using the formula:

Q1 = m1 * c1 * (T1 - T)

Where: - Q1 is the heat lost by the copper block - m1 is the mass of the copper block (150 g) - c1 is the specific heat capacity of copper (0.39 J/g°C) - T1 is the initial temperature of the copper block (100°C) - T is the final temperature of the system (unknown)

The heat gained by the aluminum calorimeter and water can be calculated using the formula:

Q2 = (m2 * c2 + m3 * c3) * (T - T2)

Where: - Q2 is the heat gained by the aluminum calorimeter and water - m2 is the mass of the aluminum calorimeter (100 g) - c2 is the specific heat capacity of aluminum (0.897 J/g°C) - m3 is the mass of the water (200 g) - c3 is the specific heat capacity of water (4.18 J/g°C) - T2 is the initial temperature of the water (10°C)

Since the heat lost by the copper block is equal to the heat gained by the aluminum calorimeter and water, we can set Q1 equal to Q2 and solve for T:

m1 * c1 * (T1 - T) = (m2 * c2 + m3 * c3) * (T - T2)

Now we can substitute the given values into the equation and solve for T.

Calculation Steps:

1. Substitute the given values into the equation:

150 g * 0.39 J/g°C * (100°C - T) = (100 g * 0.897 J/g°C + 200 g * 4.18 J/g°C) * (T - 10°C)

2. Simplify the equation:

58.5 g * (100°C - T) = (89.7 J/°C + 836 J/°C) * (T - 10°C)

3. Expand and rearrange the equation:

5850°C - 58.5gT = 926.7T - 9267°C

4. Combine like terms:

9850.7°C = 985.2gT

5. Solve for T:

T = 9850.7°C / 985.2g ≈ 10°C

Therefore, the final temperature of the system is approximately 10°C.

Please note that the above calculation assumes that there is no heat loss to the surroundings and that the specific heat capacities remain constant over the temperature range.