Question

С вертолета двигавшегося со скоростью 40 м\с в горизонтальном направлении , сброшен груз без парашюта. С какой скоростью будет двигаться груз относительно Земли через 3 секунды после начала своего движения?

Answer 1

V=v0+gt=40 м/с + 30 м/с =70 м/с 

Answer 2

Calculation of the Speed of the Object

To calculate the speed of the object relative to the Earth after 3 seconds, we need to consider the initial speed of the helicopter and the time elapsed.

Given: - Initial speed of the helicopter: 40 m/s (in the horizontal direction) - Time elapsed: 3 seconds

To find the speed of the object relative to the Earth after 3 seconds, we need to determine the horizontal component of the object's velocity. Since the object was dropped from the helicopter without a parachute, we can assume that there is no vertical acceleration acting on the object.

Therefore, the horizontal component of the object's velocity will remain constant at 40 m/s throughout its motion.

The speed of the object relative to the Earth after 3 seconds will be 40 m/s.

Please let me know if there is anything else I can help you with!