Question

Температура нагревателя 150 градусов Цельсия а холодильника 25 градусов Цельсия . Найти кпд тепловой машины

Answer 1

Дано T1 =423 К    T2 =298 К    КПД - ?

КПД идеальной тепловой машины
КПД = (T1-T2)/T1=125/423=0,2955
КПД =29,55 %

Answer 2

Calculation of the Efficiency of a Heat Engine

To calculate the efficiency of a heat engine, we need to know the temperatures of the hot and cold reservoirs. In this case, the temperature of the heater is 150 degrees Celsius, and the temperature of the refrigerator is 25 degrees Celsius.

The efficiency of a heat engine can be calculated using the formula:

Efficiency = (T1 - T2) / T1 * 100%

Where: - T1 is the temperature of the hot reservoir (heater) - T2 is the temperature of the cold reservoir (refrigerator)

Let's substitute the given values into the formula:

Efficiency = (150 - 25) / 150 * 100%

Calculating this expression, we find:

Efficiency = 83.33%

Therefore, the efficiency of the heat engine is approximately 83.33%.