Question

Тепловой двигатель за цикл работы получает от нагревателя количество теплоты равное 3 кДж, и отдаёт холодильнику 2,4 кДж. Определите КПД двигателя.

Answer 1

Дано:
Q1= 3 кДж
Q2= 2,4 кДж

Найти:
КПД=?%

Си:
3 кДж= 3000 Дж
2,4 кДж= 2400 Дж

Решение:
КПД= Q1-Q2/Q1*100%
КПД= 3000-2400/3000*100%= 20%

Ответ: 20%

Answer 2

Calculating the Efficiency of the Heat Engine

To calculate the efficiency of the heat engine, we can use the formula for efficiency:

Efficiency (η) = Output/Input

In this case, the input is the amount of heat received by the engine, and the output is the amount of heat rejected to the refrigerator.

Given: - Heat received by the engine (Q1) = 3 kJ - Heat rejected to the refrigerator (Q2) = 2.4 kJ

Using the formula, we can calculate the efficiency of the engine:

Efficiency (η) = (Q1 - Q2) / Q1

Substitute the given values: Efficiency (η) = (3 - 2.4) / 3

Efficiency (η) = 0.6 / 3

Efficiency (η) = 0.2

Answer

The efficiency of the heat engine is 20%.