Question

Ванадий альфа распад, бельта распад, гамма распад

Answer 1

1) альфа распад: 51/23V=>4/2He+47/21Sc
2) бета распад: 51/23V=>0/-1e+24Cr
3) При гамма излучении элемент не меняется

Answer 2

Vanadium Alpha Decay, Beta Decay, Gamma Decay

Vanadium Alpha Decay: Vanadium does not undergo alpha decay. Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (consisting of two protons and two neutrons) and transforms into a nucleus with atomic number two less and mass number four less. Vanadium does not exhibit this type of decay.

Vanadium Beta Decay: Vanadium undergoes beta decay. Beta decay involves the transformation of a neutron into a proton, an electron, and an antineutrino (in the case of beta-minus decay) or a positron and a neutrino (in the case of beta-plus decay). In the case of vanadium, it undergoes beta decay by emitting an electron and transforming a neutron into a proton.

Vanadium Gamma Decay: Vanadium can also undergo gamma decay. Gamma decay is the emission of gamma rays from a nucleus following other types of radioactive decay, such as alpha or beta decay. Gamma decay does not change the atomic number or mass number of the nucleus but is associated with the release of high-energy photons.

(#1)