Вопрос задан 04.05.2019 в 17:40. Предмет Физика. Спрашивает Тыщенко Алёна.

В алюминиевый сосуд массой 300 г, содержащий 1л воды при температуре 20°С, впустили стоградусный

пар. Какова масса пара, если в сосуде после его конденсации установилась температура 60°С?Рассмотрите два случая, считая, что сосуд: б) участвует в теплообмене
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Отвечает Самарская Ангелина.
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Отвечает Солдатова Варя.
Q = cmT
c*m*To+C*mc*To = c*m1*T + m1*L
4100 * 40 + 930 * 0.3*40 = 4100 * m1 * 40 + m1 * 2,3*10^6
164000 + 11160 = (164000 + 2300000)*m1
m1 = 0,071кг





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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Mass of Steam in the Aluminum Vessel

To calculate the mass of the steam in the aluminum vessel, we need to consider two cases: one where the vessel does not participate in heat exchange and another where it does participate in heat exchange.

# Case 1: Vessel Does Not Participate in Heat Exchange

In this case, we assume that the vessel does not participate in heat exchange with the surroundings. Therefore, the heat gained by the steam is equal to the heat lost by the water.

The heat gained by the steam can be calculated using the formula:

Q = m × c × ΔT

Where: - Q is the heat gained by the steam - m is the mass of the steam - c is the specific heat capacity of steam - ΔT is the change in temperature of the steam

The heat lost by the water can be calculated using the formula:

Q = m × c × ΔT

Where: - Q is the heat lost by the water - m is the mass of the water - c is the specific heat capacity of water - ΔT is the change in temperature of the water

Since the heat gained by the steam is equal to the heat lost by the water, we can equate the two equations:

m₁ × c₁ × ΔT₁ = m₂ × c₂ × ΔT₂

Where: - m₁ is the mass of the steam - c₁ is the specific heat capacity of steam - ΔT₁ is the change in temperature of the steam - m₂ is the mass of the water - c₂ is the specific heat capacity of water - ΔT₂ is the change in temperature of the water

In this case, the initial temperature of the water is 20°C, and the final temperature after condensation is 60°C. Therefore, ΔT₂ = 60 - 20 = 40°C.

We know that the specific heat capacity of water is approximately 4.18 J/g°C However, we need to find the specific heat capacity of steam and the mass of the water.

# Case 2: Vessel Participates in Heat Exchange

In this case, we assume that the vessel participates in heat exchange with the surroundings. Therefore, the heat gained by the steam is equal to the heat lost by the water plus the heat lost by the vessel.

The heat gained by the steam can be calculated using the formula:

Q = m × c × ΔT

Where: - Q is the heat gained by the steam - m is the mass of the steam - c is the specific heat capacity of steam - ΔT is the change in temperature of the steam

The heat lost by the water can be calculated using the formula:

Q = m × c × ΔT

Where: - Q is the heat lost by the water - m is the mass of the water - c is the specific heat capacity of water - ΔT is the change in temperature of the water

The heat lost by the vessel can be calculated using the formula:

Q = m × c × ΔT

Where: - Q is the heat lost by the vessel - m is the mass of the vessel - c is the specific heat capacity of aluminum - ΔT is the change in temperature of the vessel

Since the heat gained by the steam is equal to the heat lost by the water plus the heat lost by the vessel, we can equate the three equations:

m₁ × c₁ × ΔT₁ = m₂ × c₂ × ΔT₂ + m₃ × c₃ × ΔT₃

Where: - m₁ is the mass of the steam - c₁ is the specific heat capacity of steam - ΔT₁ is the change in temperature of the steam - m₂ is the mass of the water - c₂ is the specific heat capacity of water - ΔT₂ is the change in temperature of the water - m₃ is the mass of the vessel - c₃ is the specific heat capacity of aluminum - ΔT₃ is the change in temperature of the vessel

In this case, the initial temperature of the water is 20°C, and the final temperature after condensation is 60°C. Therefore, ΔT₂ = 60 - 20 = 40°C.

We know that the specific heat capacity of water is approximately 4.18 J/g°C However, we need to find the specific heat capacity of steam, the mass of the water, and the mass of the vessel.

Conclusion

To calculate the mass of the steam in the aluminum vessel, we need to consider two cases: one where the vessel does not participate in heat exchange and another where it does participate in heat exchange. In both cases, we need to know the specific heat capacity of steam, the specific heat capacity of water, and the change in temperature of the steam and water. Additionally, in the second case, we also need to know the specific heat capacity of aluminum and the change in temperature of the vessel.

Unfortunately, the specific heat capacity of steam and the mass of the water and vessel are not provided in the question. Therefore, we cannot calculate the mass of the steam in the aluminum vessel without this information.

Please provide the specific heat capacity of steam, the mass of the water, and the mass of the vessel for further calculations.

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