Question

Помогите плиииииз ))) : "Определить величину архимедовой силы, действующей на тело объемом 0,2 м3 , если оно опущено в воду на половину его объема. "

Answer 1

Дано:
V₁=0,2 м³
V=0.5V₁
Найти: F(a)
Решение:
Формула архимедовой силы
F(a)=ρgV
F(a)=ρg*0.5V₁
По справочнику:
плотность воды ρ=1000 кг/м³
F(a)=1000*10*0.5*0,2=1000 (Н)
Ответ: 1 кН

Answer 2

Calculating the Buoyant Force on a Submerged Object

To determine the buoyant force acting on an object submerged in water, we can use the formula for buoyant force:

Buoyant force = *density of fluid* × *volume of fluid displaced* × *acceleration due to gravity*

In this case, the object is submerged in water, so the density of the fluid is the density of water, which is approximately 1000 kg/m^3. The volume of fluid displaced is the volume of the submerged part of the object.

Calculation

Given: - Volume of the object (V) = 0.2 m^3 - Submerged volume (V_sub) = 0.2 m^3 / 2 = 0.1 m^3 - Density of water (ρ) = 1000 kg/m^3 - Acceleration due to gravity (g) = 9.81 m/s^2

Using the formula for buoyant force:

Buoyant force = ρ × V_sub × g

Substituting the given values:

Buoyant force = 1000 kg/m^3 × 0.1 m^3 × 9.81 m/s^2 Buoyant force ≈ 981 N

So, the buoyant force acting on the object submerged in water is approximately 981 Newtons.