Question

к 5 кг воды при 12 градусов долили в горячую воду при 50 градусов получив смесь температурой 30 градусов сколько воды долили

Answer 1

Уравнение теплового баланса
Qпол=Qотд
Qпол=с*m1*(30-12)
Qотд=c*m2(50-30)
m2 нужно найти приравниваем выражения и сокращаем c (удельную теплоемкость)
m1*18=m2*20
m2=m1*18/20=5*18/20=4.5кг

Answer 2

Calculating the Amount of Water Added

To calculate the amount of water added, we can use the principle of mixtures. The formula for the principle of mixtures is:

m1 * t1 + m2 * t2 = (m1 + m2) * t

Where: - m1 = mass of the first substance - t1 = temperature of the first substance - m2 = mass of the second substance - t2 = temperature of the second substance - t = temperature of the mixture

Given: - m1 = 5 kg - t1 = 12°C - t2 = 50°C - t = 30°C

We need to find m2, the mass of the second substance (water) added to the mixture.

Using the formula, we can rearrange it to solve for m2:

m2 = (m1 * t1 + m2 * t2 - (m1 + m2) * t) / (t - t2)

Substitute the given values and solve for m2.

m2 = (5 * 12 + m2 * 50 - (5 + m2) * 30) / (30 - 50)

m2 = (60 + 50m2 - 150 - 30m2) / (-20)

m2 = (60 - 150 + 50m2 - 30m2) / (-20)

m2 = (-90 + 20m2) / (-20)

m2 = 4.5 - m2

2m2 = 4.5

m2 = 2.25 kg

So, 2.25 kg of water was added to the mixture.