Question

При погружении в некоторую жидкость тело вытеснило 0,2 кв дм этой жидкости. Сёму равна выталкивающая сила, действующая на это тело в воде?

Answer 1

Fa=pgV
p= 1000кг/м3
g=10н/кг
V=0,2дм2  = 0,002м2
Fa= 1000*10* 0,002 =20 н
Fa=20H

Answer 2

Calculation of Buoyant Force

When an object is submerged in a fluid, it displaces an amount of fluid equal to its own volume. In this case, the body has displaced 0.2 cubic decimeters (0.2 L) of the liquid.

The buoyant force acting on the body submerged in the liquid is equal to the weight of the liquid displaced by the body. This can be calculated using the formula:

Buoyant force = weight of the displaced liquid

Calculation

Given that the body has displaced 0.2 cubic decimeters of the liquid, we can calculate the buoyant force by determining the weight of this displaced liquid.

The weight of the displaced liquid can be calculated using the density of the liquid and the acceleration due to gravity. The formula for the weight of the displaced liquid is:

Weight = density × volume × acceleration due to gravity

Density of the Liquid

To proceed with the calculation, we need to know the density of the specific liquid in which the body is submerged. Once we have the density, we can use it in the buoyant force calculation formula to determine the force acting on the body.

Please provide the density of the liquid in order to proceed with the calculation of the buoyant force acting on the body.